Algebra · real student question

Solve for x: 3x + 5 = 30 + 5.

Question

Solve for xx:

3x+5=30+53x+5=30+5

Step-by-step solution

  1. Simplify the right side before doing anything else. It is pure arithmetic:

    30+5=353x+5=3530+5=35\qquad\Longrightarrow\qquad 3x+5=35

    Missing that trailing +5+5 and solving 3x+5=303x+5=30 instead is the one real trap here, and it produces the wrong answer 253\tfrac{25}{3}.

  2. Spot the shortcut. Both sides carry the same constant +5+5, so subtracting 55 from each side removes it entirely — no fractions can arise:

    3x=303x=30

  3. Divide both sides by 3.

    x=303=10x=\frac{30}{3}=10

    Because 3030 is a multiple of 33, the answer is a whole number — another sign that the right side was read correctly.

  4. Compare with the misread version. Had the equation truly been 3x+5=303x+5=30, the result would be 3x=253x=25 and x=2538.33x=\tfrac{25}{3}\approx8.33. The presence or absence of that final +5+5 is the whole difference between a clean integer and a fraction.

  5. Verify in the original equation. Left: 3(10)+5=353(10)+5=35. Right: 30+5=3530+5=35 ✓. Both sides equal 3535, confirming x=10x=10.

Answer

x=10x=10

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