Algebra · real student question

Solve for x: 20x + 10x = 100.

Question

Solve for xx:

20x+10x=10020x+10x=100

Step-by-step solution

  1. Combine the like terms on the left. Both terms are multiples of xx, so add their coefficients:

    20x+10x=(20+10)x=30x20x+10x=(20+10)x=30x

    The equation becomes

    30x=10030x=100

  2. Divide both sides by 30.

    x=10030x=\frac{100}{30}

  3. Reduce the fraction. Numerator and denominator share the factor 1010:

    10030=100÷1030÷10=103\frac{100}{30}=\frac{100\div10}{30\div10}=\frac{10}{3}

    Leaving the answer as 10030\tfrac{100}{30} is not wrong arithmetically but is not in lowest terms, which is usually what is asked for.

  4. Give the decimal, and note it does not terminate.

    x=103=3.33.33x=\frac{10}{3}=3.\overline{3}\approx3.33

    Because the denominator 33 is not built only from 22s and 55s, the decimal repeats forever — so the fraction is the exact answer.

  5. Verify by substitution. 20103+10103=2003+1003=3003=10020\cdot\tfrac{10}{3}+10\cdot\tfrac{10}{3}=\tfrac{200}{3}+\tfrac{100}{3}=\tfrac{300}{3}=100 ✓, exact in fraction arithmetic with no rounding.

Answer

x=10030=1033.33x=\frac{100}{30}=\frac{10}{3}\approx 3.33

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