Algebra · real student question

Solve for x: 122400000 + 0.72x + 2x + 1020000 + 400000 + 0.13(122400000 - 1200x) = 1200x.

Question

Solve for xx:

122400000+0.72x+2x+1020000+400000+0.13(1224000001200x)=1200x122400000+0.72x+2x+1020000+400000+0.13\left(122400000-1200x\right)=1200x

Step-by-step solution

  1. Combine the loose xx-terms. Here the two unbracketed xx-terms are 0.72x0.72x and 2x2x:

    0.72x+2x=2.72x0.72x+2x=2.72x

    This is the only difference from the version with 12x12x, and it changes nothing about the method — only the final coefficient.

  2. Add the constants outside the bracket.

    122400000+1020000+400000=123820000122400000+1020000+400000=123820000

  3. Expand the 13% bracket. Multiply through:

    0.13×122400000=15912000,0.13×1200x=156x0.13\times 122400000=15912000,\qquad 0.13\times 1200x=156x

    so the bracket becomes 15912000156x15912000-156x.

  4. Collect once more. Constants: 123820000+15912000=139732000123820000+15912000=139732000. The xx-terms:

    2.72x156x=153.28x2.72x-156x=-153.28x

    so the equation reads 139732000153.28x=1200x139732000-153.28x=1200x.

  5. Solve. Adding 153.28x153.28x to both sides gives

    139732000=1353.28xx=1397320001353.28=103254.3154139732000=1353.28x\quad\Longrightarrow\quad x=\frac{139732000}{1353.28}=103254.3154\ldots

  6. Verify. Putting x=103254.3154x=103254.3154 into the original expression gives 123905178.53123905178.53 on the left and 1200x=123905178.531200x=123905178.53 on the right, so

    x103254.32x\approx 103254.32

Answer

x=1397320001353.28103254.32x=\frac{139732000}{1353.28}\approx 103254.32

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