Algebra · real student question

Solve for x: 122400000 + 0.72x + 12x + 1020000 + 400000 + 0.13(122400000 - 1200x) = 1200x.

Question

Solve for xx:

122400000+0.72x+12x+1020000+400000+0.13(1224000001200x)=1200x122400000+0.72x+12x+1020000+400000+0.13\left(122400000-1200x\right)=1200x

Step-by-step solution

  1. Combine the xx-terms that are already loose. On the left, 0.72x0.72x and 12x12x are like terms:

    0.72x+12x=12.72x0.72x+12x=12.72x

    Do this before touching the bracket — it keeps the bookkeeping short.

  2. Add the plain constants. Still on the left, outside the bracket:

    122400000+1020000+400000=123820000122400000+1020000+400000=123820000

    The equation is now

    123820000+12.72x+0.13(1224000001200x)=1200x123820000+12.72x+0.13(122400000-1200x)=1200x

  3. Distribute the 13%. The bracket contributes both a constant and an xx-term:

    0.13×122400000=15912000,0.13×1200x=156x0.13\times 122400000=15912000,\qquad 0.13\times 1200x=156x

    so 0.13(1224000001200x)=15912000156x0.13(122400000-1200x)=15912000-156x. The minus sign belongs to the xx-term, which is where sign slips usually happen.

  4. Collect each kind of term once more.

    123820000+15912000=139732000,12.72x156x=143.28x123820000+15912000=139732000,\qquad 12.72x-156x=-143.28x

    giving

    139732000143.28x=1200x139732000-143.28x=1200x

  5. Move every xx to the right. Adding 143.28x143.28x to both sides:

    139732000=1200x+143.28x=1343.28x139732000=1200x+143.28x=1343.28x

    Notice the coefficient is 1343.281343.28, not 12001200: the 143.28x-143.28x that came out of the bracket has to be carried across.

  6. Divide and check.

    x=1397320001343.28=104022.9885x=\frac{139732000}{1343.28}=104022.9885\ldots

    Substituting x=104022.9885x=104022.9885 back gives 124827586.21124827586.21 on both sides, so

    x104022.99x\approx 104022.99

Answer

x=1397320001343.28104022.99x=\frac{139732000}{1343.28}\approx 104022.99

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