Algebra · real student question

Rewrite in simplest terms: -(-9q + 3r) + 6r - 2(-4r + 9q).

Question

Rewrite in simplest terms:

(9q+3r)+6r2(4r+9q)-(-9q+3r)+6r-2(-4r+9q)

Step-by-step solution

  1. Treat the leading minus as multiplication by 1-1. A bare minus in front of a bracket is the most common place to lose a sign, so make it explicit:

    (9q+3r)=(1)(9q)+(1)(3r)=9q3r-(-9q+3r)=(-1)(-9q)+(-1)(3r)=9q-3r

    Both signs inside flip — not just the first one.

  2. Distribute the 2-2 over the second bracket. Again every term inside is affected:

    2(4r+9q)=(2)(4r)+(2)(9q)=8r18q-2(-4r+9q)=(-2)(-4r)+(-2)(9q)=8r-18q

    The product of two negatives gives +8r+8r, while 29q-2\cdot 9q gives 18q-18q.

  3. Rewrite the whole expression with no brackets left.

    9q3r+6r+8r18q9q-3r+6r+8r-18q

  4. Collect like terms, one variable at a time. The qq terms:

    9q18q=9q9q-18q=-9q

    The rr terms:

    3r+6r+8r=11r-3r+6r+8r=11r

    so the expression simplifies to 9q+11r-9q+11r. Terms in qq and rr can never be merged with each other — they are unlike.

  5. Check by substituting numbers. Take q=1q=1, r=2r=2. Original: (9+6)+122(8+9)=3+122=13-(-9+6)+12-2(-8+9)=3+12-2=13. Simplified: 9(1)+11(2)=9+22=13  -9(1)+11(2)=-9+22=13\;\checkmark. A second test with q=1q=-1, r=0r=0 gives (9)+02(9)=9+18=9-(9)+0-2(-9)=-9+18=9 and 9(1)+0=9  -9(-1)+0=9\;\checkmark. Two independent values are enough to confirm a linear expression in two variables.

Answer

9q+11r-9q+11r

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