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Algebra · real student question

Rewrite in simplest terms: -(-9q + 3r) + 6r - 2(-4r + 9q).

Question

Rewrite in simplest terms:

−(−9q+3r)+6r−2(−4r+9q)-(-9q+3r)+6r-2(-4r+9q)

Step-by-step solution

  1. Treat the leading minus as multiplication by −1-1. A bare minus in front of a bracket is the most common place to lose a sign, so make it explicit:

    −(−9q+3r)=(−1)(−9q)+(−1)(3r)=9q−3r-(-9q+3r)=(-1)(-9q)+(-1)(3r)=9q-3r

    Both signs inside flip — not just the first one.

  2. Distribute the −2-2 over the second bracket. Again every term inside is affected:

    −2(−4r+9q)=(−2)(−4r)+(−2)(9q)=8r−18q-2(-4r+9q)=(-2)(-4r)+(-2)(9q)=8r-18q

    The product of two negatives gives +8r+8r, while −2⋅9q-2\cdot 9q gives −18q-18q.

  3. Rewrite the whole expression with no brackets left.

    9q−3r+6r+8r−18q9q-3r+6r+8r-18q

  4. Collect like terms, one variable at a time. The qq terms:

    9q−18q=−9q9q-18q=-9q

    The rr terms:

    −3r+6r+8r=11r-3r+6r+8r=11r

    so the expression simplifies to −9q+11r-9q+11r. Terms in qq and rr can never be merged with each other — they are unlike.

  5. Check by substituting numbers. Take q=1q=1, r=2r=2. Original: −(−9+6)+12−2(−8+9)=3+12−2=13-(-9+6)+12-2(-8+9)=3+12-2=13. Simplified: −9(1)+11(2)=−9+22=13  ✓-9(1)+11(2)=-9+22=13\;\checkmark. A second test with q=−1q=-1, r=0r=0 gives −(9)+0−2(−9)=−9+18=9-(9)+0-2(-9)=-9+18=9 and −9(−1)+0=9  ✓-9(-1)+0=9\;\checkmark. Two independent values are enough to confirm a linear expression in two variables.

Answer

−9q+11r-9q+11r

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