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Algebra · real student question

Solve x/(x + 100) - (x + 25)/(x + 125) = 0.1.

Question

Solve

xx+100−x+25x+125=0.1\frac{x}{x+100}-\frac{x+25}{x+125}=0.1

Step-by-step solution

  1. Note the domain and rewrite 0.10.1 as a fraction. The denominators vanish at x=−100x=-100 and x=−125x=-125, so those values are excluded from the start. Also write 0.1=1100.1=\dfrac{1}{10} so the whole equation stays in exact arithmetic.

  2. Combine the left side over the common denominator (x+100)(x+125)(x+100)(x+125).

    x(x+125)−(x+25)(x+100)(x+100)(x+125)\frac{x(x+125)-(x+25)(x+100)}{(x+100)(x+125)}

    Expanding the two products:

    x(x+125)=x2+125x,(x+25)(x+100)=x2+125x+2500x(x+125)=x^{2}+125x,\qquad (x+25)(x+100)=x^{2}+125x+2500

  3. Watch the numerator collapse to a constant. The quadratic and the linear terms cancel completely:

    (x2+125x)−(x2+125x+2500)=−2500\left(x^{2}+125x\right)-\left(x^{2}+125x+2500\right)=-2500

    so the equation is simply

    −2500(x+100)(x+125)=110\frac{-2500}{(x+100)(x+125)}=\frac{1}{10}

    This is the structural heart of the problem: the left side is always negative wherever (x+100)(x+125)>0(x+100)(x+125)>0, so the only hope of matching a positive 110\tfrac{1}{10} is the interval −125<x<−100-125<x<-100.

  4. Cross-multiply and expand.

    −25000=(x+100)(x+125)=x2+225x+12500-25000=(x+100)(x+125)=x^{2}+225x+12500

    ⟹ x2+225x+37500=0\Longrightarrow\ x^{2}+225x+37500=0

  5. Compute the discriminant. With a=1a=1, b=225b=225, c=37500c=37500:

    b2−4ac=50625−150000=−99375<0b^{2}-4ac=50625-150000=-99375<0

    A negative discriminant means no real roots, so the original equation has no real solution. (Consistent with step 3: on −125<x<−100-125<x<-100 the product (x+100)(x+125)(x+100)(x+125) has maximum magnitude far too small to give −25000-25000.)

  6. Report the complex roots if they are wanted. Since 99375=625⋅15999375=625\cdot 159, −99375=25i159\sqrt{-99375}=25i\sqrt{159} and

    x=−225±25i1592=−112.5±157.619ix=\frac{-225\pm 25i\sqrt{159}}{2}=-112.5\pm 157.619i

    Substituting either value back into the original expression reproduces 0.10.1 to machine precision.

Answer

No real solution; the complex roots are x=−225±25i1592\text{No real solution; the complex roots are } x=\frac{-225\pm 25i\sqrt{159}}{2}

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