Algebra · real student question

Solve 31192041.56x + 31719594.84x + 24088814.72x = 99464.37 for x.

Question

Solve for xx:

31192041.56x+31719594.84x+24088814.72x=99464.3731192041.56x+31719594.84x+24088814.72x=99464.37

Step-by-step solution

  1. Notice that every term on the left is a like term. Each contains xx to the first power, so the distributive property lets them be merged into a single coefficient. No expansion, substitution or system solving is needed — this is a one-step equation dressed up in large numbers.

  2. Add the three coefficients.

    31,192,041.56+31,719,594.84=62,911,636.4031{,}192{,}041.56+31{,}719{,}594.84=62{,}911{,}636.40

    62,911,636.40+24,088,814.72=87,000,451.1262{,}911{,}636.40+24{,}088{,}814.72=87{,}000{,}451.12

    Adding in two stages keeps the decimal alignment checkable; all three values carry exactly two decimal places, so the sum must too.

  3. Rewrite the equation in one-term form.

    87,000,451.12x=99,464.3787{,}000{,}451.12\,x=99{,}464.37

  4. Divide both sides by the coefficient.

    x=99,464.3787,000,451.12=0.0011432627x=\frac{99{,}464.37}{87{,}000{,}451.12}=0.0011432627

    The answer is small because the right side is roughly 10510^5 while the coefficient is roughly 8.7×1078.7\times10^7 — a ratio near 10310^{-3}, which is a useful order-of-magnitude check before doing the division.

  5. Verify by substitution. 87,000,451.12×0.0011432627=99,464.370087{,}000{,}451.12\times0.0011432627=99{,}464.3700, matching the right-hand side to four decimal places ✓. Keeping ten significant figures matters here: rounding xx to 0.001140.00114 would reproduce only 99,18099{,}180, an error of about \284$.

Answer

x0.0011432627x\approx0.0011432627

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