Algebra · real student question

A phone plan costs 30 dollars per month plus 0.05 dollars per minute of talk and 0.10 dollars per text sent (received texts are free). Write an expression for the monthly cost using t minutes and x texts, then find the cost for (t, x) = (100, 50), (124, 26), (75, 75), (80, 95) and (50, 100).

Question

A cell phone provider charges \30eachmonthfortheplan,pluseach month for the plan, plus$0.05foreveryminuteoftalkandfor every minute of talk and$0.10$ for every text sent (received texts are free).

(a) Write an algebraic expression for the monthly cost, where tt is the number of talk minutes and xx is the number of texts sent.

(b) Find the cost for (t,x)=(100,50)(t,x)=(100,50), (124,26)(124,26), (75,75)(75,75), (80,95)(80,95) and (50,100)(50,100).

(c) Is it cheaper to talk more and text less, or to text more and talk less?

Step-by-step solution

  1. (a) Identify the fixed part and the variable parts. The \30$ is charged whether or not the phone is used, so it is a constant term. The other two charges are rates — dollars per unit — so each becomes a coefficient times its variable:

    C=30+0.05t+0.10xC=30+0.05t+0.10x

    Received texts contribute nothing, which is why only sent texts appear.

  2. (b) Evaluate the first two rows. Substitute and keep the two rate terms separate:

    (100,50): 30+0.05(100)+0.10(50)=30+5+5=$40.00(100,50):\ 30+0.05(100)+0.10(50)=30+5+5=\$40.00

    (124,26): 30+0.05(124)+0.10(26)=30+6.20+2.60=$38.80(124,26):\ 30+0.05(124)+0.10(26)=30+6.20+2.60=\$38.80

  3. Evaluate the remaining three rows.

    (75,75): 30+3.75+7.50=$41.25(75,75):\ 30+3.75+7.50=\$41.25

    (80,95): 30+4.00+9.50=$43.50(80,95):\ 30+4.00+9.50=\$43.50

    (50,100): 30+2.50+10.00=$42.50(50,100):\ 30+2.50+10.00=\$42.50

  4. Collect the table.

    Talk (min)Texts sentTotal cost
    10050$40.00
    12426$38.80
    7575$41.25
    8095$43.50
    50100$42.50
  5. (c) Compare the two rates directly. A text costs \0.10andaminutecostsand a minute costs$0.05$, so one text costs the same as two minutes of talk. For the same number of extra units it is therefore cheaper to talk more and text less.

    C=30+0.05t+0.10x; talking is half the price of texting per unit\boxed{C=30+0.05t+0.10x;\ \text{talking is half the price of texting per unit}}

  6. Check the conclusion against the table. The cheapest row, \38.80,istheonewiththefewesttexts(, is the one with the fewest texts (26),eventhoughithasthemosttalkminutes(), even though it has the most talk minutes (124).Themostexpensive,). The most expensive, $43.50,has, has 95texts.Thatorderingmatchestheratecomparisonratherthanthetotalnumberofunitsusedtexts. That ordering matches the rate comparison rather than the total number of units used —(124,26)usesuses150unitsbutcostslessthanunits but costs less than(50,100),whichusesthesame, which uses the same 150$ units.

Answer

C=30+0.05t+0.10x;$40.00, $38.80, $41.25, $43.50, $42.50C=30+0.05t+0.10x;\quad \$40.00,\ \$38.80,\ \$41.25,\ \$43.50,\ \$42.50

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