Algebra · real student question

Perform the indicated operations, write the resulting polynomial in standard form, and state its degree: (5x^2 - 7x - 1) + (3x^2 - 5x + 8) - (x^2 - 5x - 2).

Question

Perform the indicated operations. Write the resulting polynomial in standard form and indicate its degree.

(5x27x1)+(3x25x+8)(x25x2)\left(5x^{2}-7x-1\right)+\left(3x^{2}-5x+8\right)-\left(x^{2}-5x-2\right)

Step-by-step solution

  1. Deal with the subtraction sign before combining anything. The minus in front of the third bracket multiplies every term inside it, including the 2-2. Forgetting the last sign is the single most common slip in this problem, so rewrite the whole expression as a pure addition first:

    (5x27x1)+(3x25x+8)x2+5x+2\left(5x^{2}-7x-1\right)+\left(3x^{2}-5x+8\right)-x^{2}+5x+2

    Note that (5x)=+5x-(-5x)=+5x and (2)=+2-(-2)=+2.

  2. Collect the x2x^{2} terms. Like terms are those with the same power of xx, and only they may be combined:

    5x2+3x2x2=7x25x^{2}+3x^{2}-x^{2}=7x^{2}

  3. Collect the xx terms. Two negatives and one positive here:

    7x5x+5x=7x-7x-5x+5x=-7x

    The 5x-5x and +5x+5x cancel, leaving just the 7x-7x from the first polynomial.

  4. Collect the constants.

    1+8+2=9-1+8+2=9

  5. Write standard form and read off the degree. Standard form means descending powers of xx:

    7x27x+97x^{2}-7x+9

    The highest power present is x2x^{2}, so the degree is 22.

  6. Check by substituting test values. At x=0x=0 the original expression is (1)+(8)(2)=9(-1)+(8)-(-2)=9 and the result gives 99. At x=2.3x=2.3 both sides evaluate to 29.9329.93, and at x=1.7x=-1.7 both give 41.1341.13. Agreement at three separate values of xx confirms the coefficients, since two quadratics matching at three points are identical.

Answer

7x27x+9,degree 27x^{2}-7x+9,\qquad \text{degree } 2

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