Beam Span Calculator
Bending moment, required section modulus and deflection for steel, LVL and sawn timber beams — step by step
The Two Checks Every Beam Must Pass
A simply supported beam under a uniform load over a span has:
Strength is the first check. Bending stress is , so the section modulus you need is
with the allowable bending stress for the material. For a rectangle, and ; for a rolled steel shape, and come from the shape tables.
Stiffness is the second, and on residential spans it usually governs. Deflection is limited by a fraction of the span — commonly for live load and for total load on floors — and because , a 10% longer span deflects about 46% more.
Getting right: a floor load in psf becomes a line load by multiplying by the tributary width — half the joist span on each side. psf on a 12 ft tributary width is lb/ft.
Steel, LVL and Sawn Lumber
The equations above are identical for all three; the material properties and the design method are not.
| Material | Typical | Typical |
|---|---|---|
| A36 steel (ASD, ) | psi | psi |
| A992 steel, ksi | psi | psi |
| LVL / engineered lumber | – psi | – psi |
| No. 2 Douglas fir-larch, sawn | psi | psi |
- Steel is designed to AISC, and bending capacity depends on how the compression flange is braced — an unbraced beam can fail by lateral-torsional buckling well below . Web crippling and bearing at supports need checking too.
- LVL values are product-specific: the published is adjusted for depth, and the binding numbers sit in the manufacturer's ICC-ES evaluation report, not a generic table.
- Sawn lumber is designed to the NDS, where the tabulated is multiplied by adjustment factors for load duration, wet service, size and repetitive members.
These figures are for learning the calculation, not for specifying a beam. A real member must be selected from the applicable code and span tables — AISC for steel, the NDS and IRC tables for wood, the manufacturer's data for LVL — with the engineer of record responsible for the final design.
Common Mistakes to Avoid
- Mixing feet and inches. with in lb/ft and in ft gives lb·ft; multiply by 12 before dividing by an in psi.
- Checking strength and stopping. Deflection governs most residential spans. A section that passes bending can still bounce far past .
- Using the wrong support condition. is the simply supported case. A cantilever of length carries — four times the moment — and deflects .
- Confusing and . Section modulus sizes for stress; moment of inertia sizes for deflection. They are not interchangeable.
- Forgetting tributary width, point loads and self-weight. A beam under a bearing wall or a post above carries a concentrated load that a uniform-load formula ignores entirely.
- Treating a rule of thumb as a specification. Depth-to-span ratios and "one size up" habits are not design; the governing code is.
Examples
Frequently Asked Questions
For a simply supported beam under a uniform load, M = wL²/8, with w the load per unit length and L the clear span. A cantilever of the same length and load carries wL²/2 instead — four times as much — so the support condition must be identified before any formula is applied.
It depends entirely on the load. For a uniform 500 lb/ft the moment is 25,000 lb·ft = 300,000 lb·in, so with an allowable bending stress of 24,000 psi the required section modulus is 12.5 in³ — a W10×15 exceeds that in bending, but the deflection check above shows it is over the L/360 limit. The final section must be selected against the AISC specification and signed off by the engineer of record.
There is no single answer: the span depends on the load, the number of plies, the depth, and the product's published Fb and E. Work it as a calculation — find M = wL²/8, divide by the allowable bending stress for the required section modulus, then check deflection — and confirm the result against the manufacturer's span tables and ICC-ES report, which is the binding document.
Deflection scales with the fourth power of the span while moment scales with the square, so as spans get longer the stiffness demand grows far faster than the strength demand. Serviceability limits such as L/360 also exist to stop bouncy floors and cracked finishes, which occur well below any risk of failure.
Try AI-Math for Free
Get step-by-step solutions to any math problem. Upload a photo or type your question.
Start Solving