Solve trapézio com bases 5 e 8, altura 4 — A = 26

Problem

$A = \tfrac{1}{2}(b_1 + b_2) h,\ b_1=5,\ b_2=8,\ h=4$

Step-by-step solution

Área do trapézio: $A = \tfrac{1}{2}(b_1 + b_2) h$ .
Substitua $b_1 = 5$ , $b_2 = 8$ , $h = 4$ : $A = \tfrac{1}{2}(5 + 8)(4) = \tfrac{1}{2}(13)(4)$ .
Simplifique: $A = 26$ .

Answer

$A = 26$

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