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Algebra · real student question

Solve the inequality (1.5 + 0.1x)(800 - 20x) - 0.9(800 - 20x) is greater than or equal to 720.

Question

Solve the inequality

(1.5+0.1x)(800−20x)−0.9(800−20x)≥720.\left(1.5+0.1x\right)\left(800-20x\right)-0.9\left(800-20x\right)\ge 720.

Step-by-step solution

  1. Spot the repeated bracket and factor it out. Both terms on the left contain (800−20x)(800-20x), so pull it out instead of expanding twice:

    (800−20x)[(1.5+0.1x)−0.9]=(800−20x)(0.6+0.1x).\left(800-20x\right)\left[\left(1.5+0.1x\right)-0.9\right]=\left(800-20x\right)\left(0.6+0.1x\right).

    In the original setting, (1.5+0.1x)−0.9(1.5+0.1x)-0.9 is the profit per unit and (800−20x)(800-20x) is the number of units sold.

  2. Expand the product.

    (0.6+0.1x)(800−20x)=480−12x+80x−2x2=−2x2+68x+480.\left(0.6+0.1x\right)\left(800-20x\right)=480-12x+80x-2x^{2}=-2x^{2}+68x+480.

  3. Move everything to one side.

    −2x2+68x+480≥720 ⟹ −2x2+68x−240≥0.-2x^{2}+68x+480\ge 720\ \Longrightarrow\ -2x^{2}+68x-240\ge 0.

  4. Divide by -2 and flip the inequality sign. Dividing an inequality by a negative number reverses it — the step most often forgotten here:

    x2−34x+120≤0.x^{2}-34x+120\le 0.

  5. Find the roots and read the interval.

    x=34±1156−4802=34±6762=34±262=4 or 30.x=\frac{34\pm\sqrt{1156-480}}{2}=\frac{34\pm\sqrt{676}}{2}=\frac{34\pm 26}{2}=4\ \text{or}\ 30.

    An upward parabola is ≤0\le 0 between its roots, so

    4≤x≤30.4\le x\le 30.

  6. Spot-check the endpoints and an interior point. At x=4x=4: (1.9)(720)−0.9(720)=(1.0)(720)=720(1.9)(720)-0.9(720)=(1.0)(720)=720, exactly the threshold ✓. At x=17x=17 (the vertex): (3.2)(460)−0.9(460)=(2.3)(460)=1058≥720(3.2)(460)-0.9(460)=(2.3)(460)=1058\ge 720 ✓. At x=31x=31: (4.6)(180)−0.9(180)=(3.7)(180)=666<720(4.6)(180)-0.9(180)=(3.7)(180)=666<720, correctly outside.

Answer

4≤x≤304\le x\le 30

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