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Algebra · real student question

Solve for y: (y + 397)/(−409 + 397) = (x − 362)/(366 − 362).

Question

Write

y+397−409+397=x−362366−362\frac{y + 397}{-409 + 397} = \frac{x - 362}{366 - 362}

in slope-intercept form.

Step-by-step solution

  1. Recognise the two-point form. The layout

    y−y1y2−y1=x−x1x2−x1\frac{y - y_1}{y_2 - y_1} = \frac{x - x_1}{x_2 - x_1}

    matches with (x1,y1)=(362,−397)(x_1, y_1) = (362, -397) and (x2,y2)=(366,−409)(x_2, y_2) = (366, -409): the numerator y+397y + 397 is y−(−397)y - (-397), and −409+397-409 + 397 is y2−y1y_2 - y_1. So this is the line through those two points.

  2. Simplify both denominators first.

    −409+397=−12,366−362=4-409 + 397 = -12, \qquad 366 - 362 = 4

    so the equation is

    y+397−12=x−3624\frac{y + 397}{-12} = \frac{x - 362}{4}

    The slope is already visible: m=y2−y1x2−x1=−124=−3m = \dfrac{y_2 - y_1}{x_2 - x_1} = \dfrac{-12}{4} = -3.

  3. Cross-multiply.

    4(y+397)=−12(x−362)4(y + 397) = -12(x - 362)

    Keep the negative sign attached to the 1212; dropping it flips the slope and is the most common error in this rearrangement.

  4. Expand both sides.

    4y+1588=−12x+43444y + 1588 = -12x + 4344

    Here 4×397=15884 \times 397 = 1588 and 12×362=434412 \times 362 = 4344.

  5. Isolate y.

    4y=−12x+4344−1588=−12x+27564y = -12x + 4344 - 1588 = -12x + 2756

    y=−3x+689y = -3x + 689

  6. Check both original points lie on the line. At x=362x = 362: y=−1086+689=−397 ✓y = -1086 + 689 = -397 \ \checkmark. At x=366x = 366: y=−1098+689=−409 ✓y = -1098 + 689 = -409 \ \checkmark. The slope −3-3 agrees with the rise over run computed in step 2, so the conversion is correct.

Answer

y=−3x+689y = -3x + 689

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