इस पर अटक गए? इसे AI से हल करें
Algebra · real student question

Solve the inequality -4x + 6 <= 18.

Question

Solve

−4x+6≤18-4x+6\le 18

Step-by-step solution

  1. Move the constant first. Subtract 66 from both sides. Adding or subtracting never affects the direction of an inequality:

    −4x≤12-4x\le 12

  2. Divide by −4-4 and reverse the sign. Dividing by a negative number flips ≤\le into ≥\ge:

    x≥12−4=−3x\ge\frac{12}{-4}=-3

    Why the flip happens: multiplying by a negative reflects the number line, so the order of any two numbers is reversed. For instance 2≤32\le 3 but −2≥−3-2\ge -3.

  3. Alternative route that avoids the flip. You can instead add 4x4x to both sides and subtract 1818:

    6−18≤4x  ⟹  −12≤4x  ⟹  −3≤x6-18\le 4x\;\Longrightarrow\;-12\le 4x\;\Longrightarrow\;-3\le x

    which is the same statement written the other way round. Keeping the variable coefficient positive is a reliable way to sidestep sign errors.

  4. Check a value on each side of −3-3. At x=0x=0: −4(0)+6=6≤18-4(0)+6=6\le 18 ✓\checkmark (should be in the solution set). At x=−10x=-10: 40+6=46≰1840+6=46\not\le 18 ✓\checkmark (should be out). At the boundary x=−3x=-3: 12+6=18≤1812+6=18\le 18 ✓\checkmark, so the endpoint is included.

Answer

x≥−3,i.e. [−3,∞)x\ge -3,\qquad\text{i.e. }[-3,\infty)

Need to solve a different problem like this? Open the solver →