इस पर अटक गए? इसे AI से हल करें
Algebra · real student question

An arithmetic sequence has first term 2018 and common difference -5. From which term onwards does the sequence become negative?

Question

An arithmetic sequence has first term u1=2018u_1=2018 and common difference d=−5d=-5. Starting from which term does the sequence take negative values?

A. u406u_{406} B. u403u_{403} C. u405u_{405} D. u404u_{404}

Step-by-step solution

  1. Write the general term. un=2018+(n−1)(−5)=2023−5nu_n=2018+(n-1)(-5)=2023-5n The sequence decreases by 55 each step, so once it turns negative it stays negative — there is a single crossing point.

  2. Set up the inequality for negativity. 2023−5n<0⟹5n>2023⟹n>404.62023-5n<0\quad\Longrightarrow\quad 5n>2023\quad\Longrightarrow\quad n>404.6

  3. Take the smallest integer that works. Since nn must be a positive integer, the first index satisfying the inequality is n=405n=405.

  4. Evaluate the two terms around the crossing. u404=2023−2020=3>0,u405=2023−2025=−2<0u_{404}=2023-2020=3>0,\qquad u_{405}=2023-2025=-2<0

  5. Conclude. u404u_{404} is the last positive term and u405=−2u_{405}=-2 is the first negative one, so the answer is C.

Answer

u405=−2 is the first negative termu_{405}=-2\ \text{is the first negative term}

Need to solve a different problem like this? Open the solver →