Solve Kugel mit Radius 5 — V = 500/3π ≈ 523.6

Problem

$V = \tfrac{4}{3}\pi r^3,\ r = 5$

Step-by-step solution

Volumen der Kugel: $V = \tfrac{4}{3}\pi r^3$ .
Berechne $r^3 = 5^3 = 125$ .
Setze ein: $V = \tfrac{4}{3}\pi \cdot 125 = \tfrac{500}{3}\pi$ .
Näherungswert: $\approx 523.6$ .

Answer

$V = \tfrac{500}{3}\pi \approx 523.6$

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