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geometry · worked example

Solve شبه منحرف بقاعدتين 3 و 7، الارتفاع 5 — A = 25

Method: مساحة شبه المنحرف. Verified step-by-step solution with our free AI math solver.
Problem

A=12(b1+b2)h, b1=3, b2=7, h=5A = \tfrac{1}{2}(b_1+b_2)h,\ b_1=3,\ b_2=7,\ h=5

Step-by-step solution

  1. طبّق A=12(b1+b2)hA = \tfrac{1}{2}(b_1 + b_2) h.

  2. التعويض: A=12(3+7)(5)=12(10)(5)=25A = \tfrac{1}{2}(3 + 7)(5) = \tfrac{1}{2}(10)(5) = 25.

Answer

A=25A = 25

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