Problem∫2sinx dx\int 2\sin x \, dx∫2sinxdxStep-by-step solutionPull constant: 2∫sinx dx2 \int \sin x \, dx2∫sinxdx.∫sinx dx=−cosx+C\int \sin x \, dx = -\cos x + C∫sinxdx=−cosx+C.Multiply: −2cosx+C-2\cos x + C−2cosx+C.Answer−2cos(x)+C-2\cos(x) + C−2cos(x)+CWant to solve a different problem? Open the integral solver →Related worked examples/solve/calculus/integral-of-sin-x-dx