Z-Score Calculator

Compute z-scores and find normal-distribution probabilities with AI-powered step-by-step solutions

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Math Input
z-score for x = 85, mean = 70, sd = 10
Find P(Z < 1.5) using the standard normal
Find the value with z-score 2 in a distribution with mean 100 and sd 15
Compare z-scores for x=78 in N(70, 5) vs x=85 in N(80, 10)

What is a Z-Score?

A z-score (also called a standard score) measures how many standard deviations a value is from the mean:

z=xμσz = \frac{x - \mu}{\sigma}

where xx is the raw value, μ\mu is the population mean, and σ\sigma is the population standard deviation.

Interpretation:

  • z=0z = 0: the value equals the mean.
  • z=1z = 1: one standard deviation above the mean.
  • z=2z = -2: two standard deviations below the mean.
  • z>2|z| > 2 is conventionally 'unusual'; z>3|z| > 3 is 'extreme'.

Why standardize?

  • Comparability: z-scores let you compare values from different distributions (e.g., a z=1.5z = 1.5 on an SAT math test vs a z=1.5z = 1.5 on a verbal test means the same relative performance).
  • Probability lookup: if the underlying distribution is approximately normal, zz maps directly to a probability via the standard normal CDF Φ(z)\Phi(z).
  • Outlier detection: large z|z| flags potential outliers.

Sample version: when working from sample data, replace μ\mu with xˉ\bar{x} and σ\sigma with ss:

z=xxˉsz = \frac{x - \bar{x}}{s}

How to Compute and Use Z-Scores

Step-by-Step

  1. Identify the value xx, the mean μ\mu (or xˉ\bar{x}), and the standard deviation σ\sigma (or ss).
  2. Subtract the mean: xμx - \mu.
  3. Divide by the standard deviation: z=(xμ)/σz = (x - \mu)/\sigma.

Reverse: Find xx from zz

x=μ+zσx = \mu + z\sigma

Useful when given a percentile and asked for the corresponding raw value.

Probability via the Standard Normal

For a normally distributed variable XN(μ,σ2)X \sim N(\mu, \sigma^2), the standardized variable Z=(Xμ)/σZ = (X - \mu)/\sigma follows the standard normal N(0,1)N(0, 1).

Common probabilities:

zP(Z<z)P(Z < z)
2-20.02280.0228
1-10.15870.1587
000.50000.5000
110.84130.8413
1.6451.6450.95000.9500
1.961.960.97500.9750
220.97720.9772
2.5762.5760.99500.9950

Symmetry: P(Z<z)=1P(Z<z)P(Z < -z) = 1 - P(Z < z).

Empirical Rule (68-95-99.7)

For a normal distribution:

  • ~68% of values fall within ±1σ\pm 1\sigma of the mean.
  • ~95% within ±2σ\pm 2\sigma.
  • ~99.7% within ±3σ\pm 3\sigma.

This is the foundation for confidence intervals and many quick estimates.

Critical Z-Values for Confidence Intervals

Confidence levelzz^*
90%1.6451.645
95%1.961.96
99%2.5762.576

These are the values zz^* such that P(z<Z<z)=P(-z^* < Z < z^*) = confidence level.

Common Mistakes to Avoid

  • Wrong order: z=(xμ)/σz = (x - \mu)/\sigma, not (μx)/σ(\mu - x)/\sigma. Putting the mean second flips the sign.
  • Using variance instead of standard deviation: divide by σ\sigma, not σ2\sigma^2. A value 'one variance away' is meaningless — you want one standard deviation.
  • Sample vs population: with sample data, use xˉ\bar{x} and ss. With known parameters, use μ\mu and σ\sigma. Conflating them inflates/deflates z-scores.
  • Assuming normality without checking: z-scores can be computed for any distribution, but the probability lookup Φ(z)\Phi(z) only applies if the underlying distribution is normal (or approximately so by the CLT).
  • Forgetting the sign: z=2z = -2 means 'below the mean.' Reporting z=2z = 2 misrepresents direction.
  • Confusing one-tailed and two-tailed probabilities: P(Z>2)P(|Z| > 2) is both tails combined (0.0456\approx 0.0456). P(Z>2)P(Z > 2) is one tail (0.0228\approx 0.0228). Read the question carefully.

Examples

Step 1: z=(xμ)/σ=(8570)/10z = (x - \mu)/\sigma = (85 - 70)/10
Step 2: =15/10=1.5= 15/10 = 1.5
Step 3: Interpretation: 85 is 1.5 standard deviations above the mean
Answer: z=1.5z = 1.5

Step 1: Use x=μ+zσx = \mu + z\sigma
Step 2: x=100+215=100+30=130x = 100 + 2 \cdot 15 = 100 + 30 = 130
Answer: x=130x = 130

Step 1: z1=(7870)/5=8/5=1.6z_1 = (78 - 70)/5 = 8/5 = 1.6
Step 2: z2=(8580)/10=5/10=0.5z_2 = (85 - 80)/10 = 5/10 = 0.5
Step 3: x1x_1 is 1.6 sd above its mean; x2x_2 is only 0.5 sd above its mean
Step 4: Therefore x1x_1 is relatively further from its mean — a better score in relative terms
Answer: z1=1.6z_1 = 1.6, z2=0.5z_2 = 0.5; x1x_1 is the relatively more impressive value

Frequently Asked Questions

A negative z-score means the value is below the mean. z = -1 means one standard deviation below the mean; z = -2 means two standard deviations below.

Yes — you can compute a z-score for any distribution with a finite mean and standard deviation. However, mapping z to a probability via Φ(z) is only valid when the underlying distribution is normal (or approximately so by the Central Limit Theorem for large samples).

By convention |z| > 2 is 'unusual' (outside 95% of normal data) and |z| > 3 is 'extreme' (outside 99.7%). These thresholds are heuristic — robust outlier rules like IQR can be more reliable for skewed data.

Both standardize a value. Z assumes the population standard deviation is known and the sampling distribution is normal. T uses the sample standard deviation and follows a t-distribution (heavier tails for small n). For n ≥ 30, t and z are nearly indistinguishable.

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