Significant Figures Calculator

Count sig figs, round to any number of them, and get the right sig figs out of a calculation
How many significant figures are in 0.004070?
Round 0.0027495 to 3 significant figures
4.56 x 1.4 to the correct number of significant figures
12.11 + 18.0 + 1.013 to the correct number of significant figures

Which Digits Actually Count

Significant figures are the digits in a measurement that carry real information. Read the number left to right and apply four rules:

  1. Every non-zero digit counts. 47.347.3 has 3.
  2. Zeros between non-zero digits count. 20052005 has 4.
  3. Leading zeros never count. They only place the decimal point, so 0.00420.0042 has 2 sig figs, not 4.
  4. Trailing zeros count only if there is a decimal point. 0.0040700.004070 has 4; 2.5002.500 has 4; but 45004500 written with no decimal point has an ambiguous 2.

The idea behind rule 3 is that 0.00420.0042 and 4.2×1034.2 \times 10^{-3} are the same measurement written two ways, and nobody thinks 4.24.2 has four digits of precision. The idea behind rule 4 is the opposite: writing the final zero in 2.5002.500 is a deliberate claim that you measured that far.

Rounding to a Given Number of Sig Figs

  1. Count from the first significant digit, not from the decimal point. In 0.00274950.0027495 the first significant digit is the 22.
  2. Mark the last digit you are keeping. For 3 sig figs that is 2,7,42,\, 7,\, 4.
  3. Look at the very next digit only. If it is 5 or more, round the kept digit up; otherwise leave it.
  4. Refill the place value with zeros so the number keeps its size.

So 0.00274950.0027495 to 3 sig figs is 0.002750.00275 — the next digit was a 99, so the 44 became a 55.

The place-value refill is where answers go wrong. Rounding 4872148\,721 to 2 sig figs gives 4900049\,000, not 4949. You must keep the zeros, otherwise you have changed the number by a factor of a thousand.

Two Different Rules for Arithmetic

Multiplication and division — count sig figs. The answer gets the same number of significant figures as the input that has the fewest. 4.56×1.4=6.3844.56 \times 1.4 = 6.384, but 1.41.4 has only 2 sig figs, so the answer is 6.46.4.

Addition and subtraction — count decimal places. The answer gets the same number of decimal places as the input with the fewest. 12.11+18.0=30.1112.11 + 18.0 = 30.11, but 18.018.0 has only one decimal place, so the answer is 30.130.1.

The mistake almost everyone makes is using the multiplication rule on a sum. In 100.0+0.234100.0 + 0.234, the 0.2340.234 has 3 sig figs, but it does not force the answer to 3 sig figs — the answer is 100.2100.2, which has 4. Precision in a sum is limited by where the uncertainty sits, not by how many digits you wrote.

Also: do not round between steps. Carry the full calculator value through and round once at the end, keeping a note of how many figures each step is entitled to.

Examples

Step 1: The leading zeros in 0.0040.004 are placeholders, so they do not count.
Step 2: Start counting at the first non-zero digit, the 44: that is figure 1.
Step 3: The 00 between 44 and 77 is trapped between non-zero digits, so it counts: figure 2.
Step 4: The 77 is figure 3.
Step 5: The final 00 is a trailing zero after a decimal point, so it counts: figure 4.
Answer: 4 significant figures

Step 1: The first significant digit is 22, so the three digits being kept are 22, 77 and 44.
Step 2: The first digit dropped is 99.
Step 3: 959 \ge 5, so round the last kept digit up: 454 \to 5.
Step 4: Rebuild the number with its original place values: 0.002750.00275.
Answer: 0.002750.00275

Step 1: Do the multiplication in full first: 4.56×1.4=6.3844.56 \times 1.4 = 6.384.
Step 2: Count the sig figs in each input: 4.564.56 has 3, 1.41.4 has 2.
Step 3: This is multiplication, so the answer takes the smaller count: 2 sig figs.
Step 4: Round 6.3846.384 to 2 sig figs. The digits kept are 66 and 33; the next digit is 88, so round up.
Step 5: 6.3846.46.384 \to 6.4
Answer: 6.46.4

Frequently Asked Questions

It depends where they sit. Zeros between non-zero digits always count (2005 has 4). Leading zeros never count (0.0042 has 2). Trailing zeros count only when a decimal point is present (2.500 has 4, but 2500 is ambiguous).

As written, 1 — the trailing zeros are ambiguous with no decimal point. Writing 100. with a trailing point makes it 3, and scientific notation removes the doubt entirely: 1 x 10^2 is 1 sig fig, 1.00 x 10^2 is 3.

Apply the rules in the order the operations happen. Work out the bracketed sum first and note how many decimal places it is entitled to, convert that into a sig fig count, then apply the multiplication rule to the next step. Keep the unrounded value in the calculator and round only at the very end.

No. Exact values — 12 in a dozen, the 2 in the formula for a circumference, a defined conversion like 1 inch = 2.54 cm — are treated as having infinitely many significant figures. Only measured quantities limit the precision of an answer.

Related Solvers

Try AI-Math for Free

Get step-by-step solutions to any math problem. Upload a photo or type your question.

Start Solving