Solve right triangle with legs 7 and 24

Problem

$a^2 + b^2 = c^2,\ a=7,\ b=24$

Step-by-step solution

Apply $a^2 + b^2 = c^2$ with $a = 7$ , $b = 24$ .
$7^2 + 24^2 = 49 + 576 = 625$ .
$c = \sqrt{625} = 25$ .
$(7, 24, 25)$ is yet another primitive Pythagorean triple — collect them; they appear in standardised tests.

Answer

$c = 25$

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