Trigonometry · real student question

Decide whether the equation 10 = 5 cos(2 pi) is true.

Question

Decide whether

10=5cos(2π)10=5\cos(2\pi)

is a true statement.

Step-by-step solution

  1. Evaluate the cosine at the full turn. An angle of 2π2\pi radians is one complete revolution, returning to the point (1,0)(1,0) on the unit circle, and cosine reads the xx-coordinate:

    cos(2π)=1\cos(2\pi)=1

  2. Compute the right-hand side.

    5cos(2π)=51=55\cos(2\pi)=5\cdot 1=5

  3. Compare the two sides. The claim reduces to

    10=510=5

    which is false. There is no variable to solve for, so the statement is simply untrue.

  4. Note the structural reason it could never hold. Because 1cosθ1-1\le\cos\theta\le 1 for every angle, the expression 5cosθ5\cos\theta is confined to [5,5][-5,5]:

    5cosθ5<10|5\cos\theta|\le 5<10

    So even if 2π2\pi were replaced by any angle, the equation 10=5cosθ10=5\cos\theta would still have no solution — the amplitude 55 is simply too small.

  5. State the conclusion. The equation is false; had it been written as 10=5cosθ10=5\cos\theta with θ\theta unknown, the solution set would be empty \checkmark.

Answer

False: 5cos(2π)=510, and 5cosθ5 for every θ\text{False: }5\cos(2\pi)=5\neq 10\text{, and }|5\cos\theta|\le 5\text{ for every }\theta

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