Trigonometry · real student question

Find the area of a sector of a circle of radius 3 metres with central angle 120 degrees, rounded to three decimal places.

Question

Find the area AA of a sector of a circle of radius r=3r=3 m with central angle θ=120\theta=120^{\circ}, rounded to three decimal places.

Step-by-step solution

  1. Convert the angle to radians before using the formula. A=12r2θA=\tfrac12 r^{2}\theta is derived from the fraction θ/(2π)\theta/(2\pi) of a full circle, so it is only valid in radians:

    θ=120×π180=2π3 rad\theta=120^{\circ}\times\frac{\pi}{180}=\frac{2\pi}{3}\ \text{rad}

    Substituting 120120 directly would overstate the area by a factor of about 5757.

  2. Square the radius.

    r2=32=9r^{2}=3^{2}=9

  3. Apply the sector-area formula.

    A=12(9)(2π3)=92π6=3πA=\frac12(9)\left(\frac{2\pi}{3}\right)=\frac{9\cdot 2\pi}{6}=3\pi

  4. Convert to a decimal.

    A=3π=9.424789.425 m2A=3\pi=9.42478\approx 9.425\ \text{m}^{2}

    A=3π9.425 m2\boxed{A=3\pi\approx 9.425\ \text{m}^{2}}

  5. Check with the fraction-of-a-circle argument. 120120^{\circ} is exactly one third of 360360^{\circ}, and the full circle has area πr2=9π\pi r^{2}=9\pi. One third of 9π9\pi is 3π3\pi ✓ — a useful shortcut whenever the angle divides 360360^{\circ} evenly.

Answer

A=3π9.425 m2A=3\pi\approx 9.425\ \text{m}^{2}

Need to solve a different problem like this? Open the solver →