Statistics · real student question

Eight sellers list the same used bass guitar at 699, 599, 699, 680, 590, 720, 650 and 800 dollars. Find the mean price to the nearest cent, the median price, and the mode price.

Question

Eight sellers list the same make and model of used bass guitar at these prices:

$699, $599, $699, $680, $590, $720, $650, $800\$699,\ \$599,\ \$699,\ \$680,\ \$590,\ \$720,\ \$650,\ \$800

(a) What is the mean price, to the nearest cent? (b) What is the median price? (c) What is the mode price?

Step-by-step solution

  1. Add the eight prices carefully. Running total:

    699+599=1298, +699=1997, +680=2677, +590=3267,699+599=1298,\ +699=1997,\ +680=2677,\ +590=3267,
    +720=3987, +650=4637, +800=5437.+720=3987,\ +650=4637,\ +800=5437.

    The total is \5437$.

  2. Divide by the count for the mean.

    xˉ=54378=679.625  $679.63.\bar{x}=\frac{5437}{8}=679.625\ \Longrightarrow\ \$679.63.

    A value of \670.63sometimesappearsonthisexercise;itisadigittransposition.Anymeanmustliebetweenthesmallestandlargestdatavalues,anditshouldsitnearthemiddleoftheclustersometimes appears on this exercise; it is a digit transposition. Any mean must lie between the smallest and largest data values, and it should sit near the middle of the cluster590800$ — a quick way to catch such an error.

  3. Sort the data before finding the median. This step cannot be skipped:

    590, 599, 650, 680, 699, 699, 720, 800.590,\ 599,\ 650,\ 680,\ 699,\ 699,\ 720,\ 800.

  4. Average the two middle values. With n=8n=8 (even), the median is the mean of the 4th and 5th entries:

    median=680+6992=13792=$689.50.\text{median}=\frac{680+699}{2}=\frac{1379}{2}=\$689.50.

  5. Find the most frequent value for the mode. Counting: 699699 appears twice; every other price appears once. So

    mode=$699.00.\text{mode}=\$699.00.

  6. Compare the three measures. Mean \679.63<medianmedian$689.50<modemode$699.Themeanispulleddownbythetwolowprices. The mean is pulled down by the two low prices 590andand599$, which is exactly the sensitivity to outliers that makes the median the more robust summary of a price list.

Answer

mean=$679.63,median=$689.50,mode=$699.00\text{mean}=\$679.63,\qquad \text{median}=\$689.50,\qquad \text{mode}=\$699.00

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