Physics · real student question

The equation d = m/V gives the density d of an object with mass m and volume V. Which is an equivalent equation solved for V: dm = V, m/d = V, d/m = V, or m - d = V?

Question

The equation

d=mVd=\frac{m}{V}

can be used to calculate the density dd of an object with mass mm and volume VV. Which is an equivalent equation solved for VV?

dm=Vmd=Vdm=Vmd=Vdm=V\qquad \frac{m}{d}=V\qquad \frac{d}{m}=V\qquad m-d=V

Step-by-step solution

  1. Get the target variable out of the denominator first. You cannot isolate VV while it sits underneath, so multiply both sides by VV (non-zero, since a real object has volume):

    dV=m.dV=m.

  2. Divide by the coefficient of V. That coefficient is dd, so

    V=md.V=\frac{m}{d}.

    This matches the second option.

  3. Check by substituting back. Putting V=mdV=\tfrac{m}{d} into the original:

    mV=mm/d=mdm=d \frac{m}{V}=\frac{m}{m/d}=m\cdot\frac{d}{m}=d\ \checkmark

  4. Test with a concrete example. A block with m=20 gm=20\ \text{g} and V=4 cm3V=4\ \text{cm}^3 has d=5 g/cm3d=5\ \text{g/cm}^3. Then md=205=4\tfrac{m}{d}=\tfrac{20}{5}=4, the correct volume, while dm=100dm=100 and dm=0.25\tfrac{d}{m}=0.25 are both wrong.

  5. Rule out the distractors by units. mm is in grams and dd in g/cm3\text{g}/\text{cm}^3, so md\tfrac{m}{d} has units g÷g/cm3=cm3\text{g}\div\text{g}/\text{cm}^3=\text{cm}^3 — a volume, as required. By contrast dmdm carries g2/cm3\text{g}^2/\text{cm}^3 and mdm-d subtracts unlike units, which is meaningless. Unit checking alone identifies the answer.

Answer

V=mdV=\frac{m}{d}

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