Physics · real student question

A unidirectional pre-preg carbon fibre is 45% resin by weight. The fibre density is 1.7 g/cm^3 and the matrix density is 1.1 g/cm^3. Calculate the fibre volume fraction Vf and the matrix volume fraction Vm as percentages to one decimal place.

Question

A unidirectional pre-preg carbon fibre is 45%45\% resin by weight. Given ρf=1.7 g/cm3\rho_f=1.7\ \text{g/cm}^3 and ρm=1.1 g/cm3\rho_m=1.1\ \text{g/cm}^3, calculate the fibre volume fraction VfV_f and the matrix volume fraction VmV_m, as percentages to one decimal place.

Step-by-step solution

  1. Read off the weight fractions. "45%45\% resin by weight" means

    Wm=0.45,Wf=10.45=0.55W_m=0.45,\qquad W_f=1-0.45=0.55

    Weight fractions and volume fractions differ whenever the two densities differ, which is exactly why the conversion is needed.

  2. Convert weights to volumes. Take a convenient 11 g of pre-preg. Since volume == mass//density, the two constituents occupy

    Wfρf=0.551.7=0.3235 cm3,Wmρm=0.451.1=0.4091 cm3\frac{W_f}{\rho_f}=\frac{0.55}{1.7}=0.3235\ \text{cm}^3,\qquad \frac{W_m}{\rho_m}=\frac{0.45}{1.1}=0.4091\ \text{cm}^3

  3. Find the total volume of that gram.

    0.3235+0.4091=0.7326 cm30.3235+0.4091=0.7326\ \text{cm}^3

    (Equivalently the composite density is 1/0.7326=1.365 g/cm31/0.7326=1.365\ \text{g/cm}^3.)

  4. Divide to get each volume fraction.

    Vf=0.32350.7326=0.4416,Vm=0.40910.7326=0.5584V_f=\frac{0.3235}{0.7326}=0.4416,\qquad V_m=\frac{0.4091}{0.7326}=0.5584

  5. Express as percentages.

    Vf=44.2%,Vm=55.8%\boxed{V_f=44.2\%,\qquad V_m=55.8\%}

  6. Check the sum and the direction of the shift. 44.2+55.8=100.0%44.2+55.8=100.0\% ✓. The resin is only 45%45\% by weight but 55.8%55.8\% by volume, which is the expected direction: the matrix is the less dense phase, so a given mass of it takes up more room. If the numbers had moved the other way, a density would have been used upside down.

Answer

Vf=44.2%,Vm=55.8%V_f=44.2\%,\quad V_m=55.8\%

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