Physics · real student question

From A a car travels in a straight line along a 10 km road and then immediately returns to A. The whole trip takes 20 minutes. Find the average speed of the car.

Question

From AA a car travels in a straight line along a road of length 10 km10\text{ km} and then immediately returns to AA. The whole trip takes 2020 minutes. Find the average speed of the car.

A. 20 km/h20\text{ km/h} B. 30 km/h30\text{ km/h} C. 60 km/h60\text{ km/h} D. 40 km/h40\text{ km/h}

Step-by-step solution

  1. Separate speed from velocity. Average speed uses the total path length travelled, while average velocity uses the displacement. The car returns to its starting point, so the displacement is zero — but the question asks for speed, so we must add both legs.

  2. Add the two legs. s=10+10=20 kms=10+10=20\text{ km}

  3. Convert the time to hours. t=20 min=2060 h=13 ht=20\text{ min}=\frac{20}{60}\text{ h}=\frac{1}{3}\text{ h}

  4. Divide total path by total time. vtb=st=2013=20×3=60 km/hv_{tb}=\frac{s}{t}=\frac{20}{\tfrac13}=20\times 3=60\text{ km/h}

  5. Check the trap answer. Using only the one-way 10 km10\text{ km} would give 30 km/h30\text{ km/h} (option B), which is exactly the mistake of confusing displacement with distance. The correct choice is C, 60 km/h60\text{ km/h}.

Answer

vtb=10+1013=60 km/hv_{tb}=\frac{10+10}{\tfrac{1}{3}}=60\ \text{km/h}

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