Geometry · real student question

Solve the cylinder surface area formula S = 2 pi r h + 2 pi r^2 for h.

Question

Marta is solving the equation

S=2πrh+2πr2S = 2\pi r h + 2\pi r^2

for hh. Which rearrangement is correct?

Step-by-step solution

  1. See what the formula is made of. SS is the total surface area of a cylinder: 2πrh2\pi r h is the curved side (a rolled-out rectangle) and 2πr22\pi r^2 is the two circular ends. Only the first term contains hh, so the second term has to be removed before dividing.

  2. Undo the addition first. Subtract 2πr22\pi r^2 from both sides:

    S2πr2=2πrhS - 2\pi r^2 = 2\pi r h

  3. Divide by the whole coefficient of hh. The coefficient is 2πr2\pi r, so divide both sides by it:

    h=S2πr22πrh = \frac{S - 2\pi r^2}{2\pi r}

  4. Split the fraction to get the tidy form. Dividing each term of the numerator separately:

    h=S2πr2πr22πr=S2πrrh = \frac{S}{2\pi r} - \frac{2\pi r^2}{2\pi r} = \frac{S}{2\pi r} - r

    So the two forms S2πr22πr\dfrac{S-2\pi r^2}{2\pi r} and S2πrr\dfrac{S}{2\pi r} - r are the same answer.

  5. Reject the near-miss options. Sr2πr\dfrac{S - r}{2\pi r} subtracts rr instead of 2πr22\pi r^2; S2πrS - \dfrac{2\pi}{r} and Sr2πS - \dfrac{r}{2\pi} never divide by the coefficient at all. Any correct answer must leave hh alone with no hh on the right.

  6. Check with numbers. Take r=3r = 3 and h=5h = 5: S=2π(3)(5)+2π(9)=30π+18π=48πS = 2\pi(3)(5) + 2\pi(9) = 30\pi + 18\pi = 48\pi. Now run the formula backwards: 48π2π(3)3=83=5\dfrac{48\pi}{2\pi(3)} - 3 = 8 - 3 = 5 ✓, recovering the original height.

Answer

h=S2πrr=S2πr22πrh = \frac{S}{2\pi r} - r = \frac{S - 2\pi r^2}{2\pi r}

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