Finance · real student question

Solve for x: 295 = x + 0.0152 + (x times 0.0152)/(1 - 0.0152).

Question

Solve for xx:

295=x+0.0152+x0.015210.0152295=x+0.0152+\frac{x\cdot 0.0152}{1-0.0152}

Step-by-step solution

  1. Move the lone constant across. Only 0.01520.0152 on its own is free of xx:

    2950.0152=x+0.0152x0.9848  294.9848=x+0.0152x0.9848.295-0.0152=x+\frac{0.0152x}{0.9848}\ \Longrightarrow\ 294.9848=x+\frac{0.0152x}{0.9848}.

    Note that 0.01520.0152 appears twice in the problem with two different roles — once as a flat amount and once as a rate. Keeping them apart is the main hazard here.

  2. Factor x out of the right-hand side.

    294.9848=x(1+0.01520.9848).294.9848=x\left(1+\frac{0.0152}{0.9848}\right).

  3. Compute the gross-up multiplier.

    0.01520.9848=0.01543461  1+0.01543461=1.01543461.\frac{0.0152}{0.9848}=0.01543461\ldots\ \Longrightarrow\ 1+0.01543461=1.01543461.

  4. Divide.

    x=294.98481.01543461=290.50103.x=\frac{294.9848}{1.01543461}=290.50103.

  5. Substitute back to confirm. The fee term is 0.0152×290.501030.9848=4.48347\dfrac{0.0152\times 290.50103}{0.9848}=4.48347, so the right side is

    290.50103+0.0152+4.48347=295.00000,290.50103+0.0152+4.48347=295.00000,

    reproducing the left side. So x290.50x\approx 290.50.

Answer

x=2950.01521+0.01520.9848290.50x=\frac{295-0.0152}{1+\frac{0.0152}{0.9848}}\approx 290.50

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