Calculus · real student question

Find the derivative of y = x^2.

Question

Find the derivative of

y=x2y=x^2

Step-by-step solution

  1. Identify the form of the function. y=x2y=x^2 is a single power of xx with a constant exponent, which is exactly the case the power rule is built for. No product, quotient, or chain rule is needed.

  2. State the power rule. For any constant exponent nn,

    ddxxn=nxn1\frac{d}{dx}x^n=n\,x^{\,n-1}

    The exponent becomes the coefficient, and the new exponent is one lower.

  3. Apply it with n = 2.

    ddxx2=2x21=2x1=2x\frac{d}{dx}x^2=2\,x^{2-1}=2x^1=2x

  4. Confirm it from the limit definition. This is where the 22 actually comes from:

    (x+h)2x2h=x2+2xh+h2x2h=2xh+h2h=2x+h\frac{(x+h)^2-x^2}{h}=\frac{x^2+2xh+h^2-x^2}{h}=\frac{2xh+h^2}{h}=2x+h

    Letting h0h\to0 leaves 2x2x ✓. The 2xh2xh cross-term of the binomial expansion is the entire source of the coefficient.

  5. Interpret the result geometrically. The derivative 2x2x says the parabola's slope is 00 at the vertex x=0x=0, negative to the left, and positive to the right, growing linearly — which matches the shape of y=x2y=x^2.

  6. Spot-check numerically. At x=2.5x=2.5 the formula predicts a slope of 55; the symmetric difference quotient f(2.5001)f(2.4999)0.0002=5.0000\frac{f(2.5001)-f(2.4999)}{0.0002}=5.0000 ✓.

Answer

dydx=2x\frac{dy}{dx}=2x

Need to solve a different problem like this? Open the solver →