Arithmetic · real student question

Write the number -6.00009 x 10^7 in decimal notation without the use of exponents.

Question

Write the number in decimal notation without the use of exponents.

6.00009×107-6.00009\times 10^{7}

Step-by-step solution

  1. Set the sign aside and read the exponent. The minus belongs to the coefficient. The exponent +7+7 is positive, so the number is large and the decimal point moves seven places right.

  2. Count the digits you already have after the point. In 6.000096.00009 there are five digits after the point: 0,0,0,0,90,0,0,0,9. Those five moves use up the existing digits, and the remaining 75=27-5=2 moves must be filled with zeros.

  3. Move the point five places, consuming the existing digits.

    6.0000960.0009600.0096000.0960000.9600009.6.00009\to 60.0009\to 600.009\to 6000.09\to 60000.9\to 600009.

    The interior zeros are placeholders and must all be carried — dropping them would give 6969 instead of 600009600009.

  4. Move the last two places, padding with zeros.

    600009600009060000900.600009\to 6000090\to 60000900.

  5. Reattach the sign.

    6.00009×107=60000900=60,000,900.-6.00009\times 10^{7}=-60000900=-60{,}000{,}900.

  6. Check by multiplying directly. 6.00009×10,000,000=60,000,9006.00009\times 10{,}000{,}000=60{,}000{,}900, and counting digits confirms the result has 88 digits, consistent with a coefficient between 11 and 1010 times 10710^{7}.

Answer

6.00009×107=60,000,900-6.00009\times 10^{7}=-60{,}000{,}900

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