Simplify
and express it as a mixed number and as a decimal.
Cancel the common factors of 2. Both and are even, so divide each by :
Since , its only prime factor is — so the reduction can continue only while the numerator stays even.
Check whether the reduction can go further. is odd, so it shares no factor of with . As is the only prime available in the denominator, the greatest common divisor is and the fraction is already in lowest terms. A gcd computation confirms ✓.
Convert to a mixed number by dividing out. How many whole s fit into ?
Since , the quotient is with remainder :
Check: ✓.
Convert to a decimal — and note it terminates. A fraction terminates exactly when its reduced denominator has only s and s as prime factors. Here the denominator is , so it terminates after at most decimal places:
This is exact, not rounded — precisely.
Verify all three forms agree. and ✓, computed in exact rational arithmetic. So , four names for one number.
Need to solve a different problem like this? Open the solver →