Arithmetic · real student question

Evaluate [(2/3 − 1/2) ÷ 1/30] × (−2 × 1/10).

Question

Evaluate

[(2312)÷130]×(2×110)\left[\left(\frac23-\frac12\right)\div\frac{1}{30}\right]\times\left(-2\times\frac{1}{10}\right)

Step-by-step solution

  1. Deal with the innermost bracket first. The denominators 33 and 22 have LCM 66:

    2312=4636=16\frac23-\frac12=\frac46-\frac36=\frac16

  2. Divide by 1/30. Dividing by a fraction means multiplying by its reciprocal, and dividing by 130\tfrac{1}{30} therefore multiplies by 30:

    16÷130=16×30=5\frac16\div\frac{1}{30}=\frac16\times 30=5

    So the whole square bracket equals 55.

  3. Evaluate the second bracket.

    2×110=210=15-2\times\frac{1}{10}=-\frac{2}{10}=-\frac15

  4. Multiply the two results.

    5×(15)=15\times\left(-\frac15\right)=-1

    1\boxed{-1}

  5. Check the sign and the structure. Exactly one negative factor appears, so the answer is negative ✓. Note the neat design: the first bracket produces 55 and the second produces 15\tfrac15 with a minus, so they are exact reciprocals up to sign — recognising that would have given the answer 1-1 in one line.

Answer

1-1

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