Algebra · real student question

Solve the equation x^2 - 25 = 0 by factoring.

Question

Solve by factoring:

x225=0x^2-25=0

Step-by-step solution

  1. Spot the pattern before choosing a method. There is no xx term, and both x2x^2 and 2525 are perfect squares with a minus sign between them. That is the signature of a difference of two squares:

    A2B2=(AB)(A+B)A^2-B^2=(A-B)(A+B)

  2. Identify AA and BB. Here A=xA=x because x2=(x)2x^2=(x)^2, and B=5B=5 because 25=5225=5^2. Substituting:

    x225=(x5)(x+5)x^2-25=(x-5)(x+5)

  3. Set the factored form to zero and split.

    (x5)(x+5)=0  x5=0 or x+5=0(x-5)(x+5)=0\ \Longrightarrow\ x-5=0\ \text{or}\ x+5=0

  4. Solve both branches.

    x=5orx=5x=5\qquad\text{or}\qquad x=-5

    The factoring route makes the negative root impossible to forget. Going straight to x2=25x^2=25 and writing x=25=5x=\sqrt{25}=5 loses the second root — the correct statement there is x=±25x=\pm\sqrt{25}.

  5. Check both values.

    5225=2525=05^2-25=25-25=0\quad\checkmark

    (5)225=2525=0(-5)^2-25=25-25=0\quad\checkmark

Answer

x=5orx=5x=5\quad\text{or}\quad x=-5

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