Algebra · real student question

Find the root of the equation x^2 - 15 = (x + 15)^2.

Question

Find the root of

x215=(x+15)2x^2 - 15 = (x + 15)^2

Step-by-step solution

  1. Expand the right-hand side.

    (x+15)2=x2+30x+225(x+15)^2 = x^2 + 30x + 225

    so the equation reads x215=x2+30x+225x^2 - 15 = x^2 + 30x + 225.

  2. Cancel the quadratic terms. Both sides carry exactly one x2x^2, so subtracting x2x^2 removes it entirely:

    15=30x+225-15 = 30x + 225

    The equation is therefore linear and has a single root — despite the squares on both sides suggesting two.

  3. Solve for x.

    30x=15225=240x=830x = -15 - 225 = -240 \quad\Longrightarrow\quad x = -8

  4. Check by substitution. Left: (8)215=6415=49(-8)^2 - 15 = 64 - 15 = 49. Right: (8+15)2=72=49(-8 + 15)^2 = 7^2 = 49. Both give 4949.

  5. Interpret geometrically. The equation asks where the parabola y=x2y = x^2 shifted down 1515 meets the same parabola shifted left 1515. Two congruent parabolas differing only by a translation cross in exactly one point — here (8,49)(-8, 49) — which is the structural reason only one root exists.

Answer

x=8x = -8

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