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Get both terms on the same side. The variable appears on the left and the right, so nothing can be divided out yet. Subtract from both sides:
The coefficient is — a small number, which is precisely why the answer will be large.
Isolate the term in . Add to both sides:
Divide by the coefficient. Dividing by is the same as multiplying by , since :
Working in fractions avoids any decimal drift: .
Verify in the original equation. Left side: . Right side: ✓. The check was also run in exact rational arithmetic, so the value is on the nose, not a rounded approximation.
Understand what the equation says. It asks for the number that drops by exactly when reduced by — so must be that , making the whole . Reading the structure this way turns the algebra into a one-line percentage argument, and it also predicts that would give , since then is of the whole.
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