Algebra · real student question

Solve for x: x = 0.4 * 200 + 0.4x.

Question

Solve for xx:

x=0.4200+0.4xx=0.4\cdot200+0.4x

Step-by-step solution

  1. Evaluate the numeric product. 0.4×200=800.4\times200=80, so

    x=80+0.4xx=80+0.4x

    The unknown now appears on both sides, which is the only real difficulty.

  2. See why you cannot simply divide. Reading the equation as x=80/0.4=200x=80/0.4=200 would ignore the 0.4x0.4x on the right. Because xx is defined partly in terms of itself, the xx terms must be gathered before any division.

  3. Move the 0.4x to the left. Subtract 0.4x0.4x from both sides and factor:

    x0.4x=80(10.4)x=800.6x=80x-0.4x=80\qquad\Longrightarrow\qquad (1-0.4)x=80\qquad\Longrightarrow\qquad 0.6x=80

    The operative coefficient is 10.4=0.61-0.4=0.6, not 0.40.4.

  4. Divide by 0.6.

    x=800.6=8006=4003=133.3133.33x=\frac{80}{0.6}=\frac{800}{6}=\frac{400}{3}=133.\overline{3}\approx133.33

    The exact fraction 4003\tfrac{400}{3} is the cleaner answer, since the decimal repeats.

  5. Compare with the sibling cases. The general solution of x=c200+cxx=c\cdot200+cx is x=200c1cx=\dfrac{200c}{1-c}: at c=0.3c=0.3 it gives 600785.71\tfrac{600}{7}\approx85.71, at c=0.35c=0.35 it gives 140013107.69\tfrac{1400}{13}\approx107.69, and at c=0.4c=0.4 it gives 4003133.33\tfrac{400}{3}\approx133.33. The growth accelerates as cc approaches 11, where the equation has no solution at all.

  6. Verify by substitution. With x=4003x=\tfrac{400}{3}: the right side is 80+0.44003=80+1603=240+1603=400380+0.4\cdot\tfrac{400}{3}=80+\tfrac{160}{3}=\tfrac{240+160}{3}=\tfrac{400}{3} ✓, identical to the left side in exact fraction arithmetic.

Answer

x=800.6=4003133.33x=\frac{80}{0.6}=\frac{400}{3}\approx 133.33

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