Algebra · real student question

Solve the inequality (2 - x - x)/3 < (1/3)(2 - 5x).

Question

Solve the inequality 2xx3<13(25x).\frac{2-x-x}{3}<\frac13\left(2-5x\right).

Step-by-step solution

  1. Tidy the numerator first. The left numerator contains two like terms: 2xx=22x2-x-x=2-2x, so the inequality is 22x3<13(25x).\frac{2-2x}{3}<\frac13(2-5x).

  2. Clear the denominators, and note the sign rule. Both sides carry a factor 13\frac13. Multiplying an inequality by a positive number preserves its direction, and 3>03>0, so the sign stays as <<: 22x<25x.2-2x<2-5x . This is the step where multiplying by a negative would have required flipping the inequality.

  3. Move the variable terms to one side. Adding 5x5x to both sides gives 2+3x<2.2+3x<2 .

  4. Isolate x. Subtracting 22 leaves 3x<03x<0, and dividing by the positive number 33 gives x<0.x<0 .

  5. Check with a test value from each side. At x=1x=-1: left =2+23=43=\frac{2+2}{3}=\frac43, right =13(2+5)=73=\frac13(2+5)=\frac73, and 43<73\frac43<\frac73 is true. At x=1x=1: left =0=0, right =13(3)=1=\frac13(-3)=-1, and 0<10<-1 is false. So the solution set is exactly x<0x<0, i.e. (,0)(-\infty,0).

Answer

x<0,that is x(,0)x<0,\qquad\text{that is } x\in(-\infty,\,0)

Need to solve a different problem like this? Open the solver →