Algebra · real student question

Solve for x: [178.29 + (1024.32 - x)] / (1279.43 + x) = 16/9.

Question

Solve for xx:

178.29+(1024.32x)1279.43+x=169\frac{178.29+(1024.32-x)}{1279.43+x}=\frac{16}{9}

Step-by-step solution

  1. Tidy the numerator before doing anything structural. The two constants combine:

    178.29+(1024.32x)=1202.61x178.29+(1024.32-x)=1202.61-x

    so the equation is 1202.61x1279.43+x=169\dfrac{1202.61-x}{1279.43+x}=\dfrac{16}{9}. Note that xx appears in both numerator and denominator with opposite signs, which is what makes the final coefficient large.

  2. Cross-multiply. For AB=CD\dfrac{A}{B}=\dfrac{C}{D} with B,D0B,D\neq 0, the equation AD=BCAD=BC is equivalent:

    9(1202.61x)=16(1279.43+x)9(1202.61-x)=16(1279.43+x)

    Keep in mind the hidden restriction 1279.43+x01279.43+x\neq 0, i.e. x1279.43x\neq -1279.43; we will check the answer against it at the end.

  3. Expand both sides.

    9×1202.61=10823.49,16×1279.43=20470.889\times 1202.61=10823.49,\qquad 16\times 1279.43=20470.88

    10823.499x=20470.88+16x10823.49-9x=20470.88+16x

  4. Collect the xx terms and the constants. Subtracting 10823.4910823.49 and 16x16x from both sides:

    25x=20470.8810823.49=9647.39-25x=20470.88-10823.49=9647.39

    The coefficient 25-25 comes from 916-9-16: because xx sat on opposite sides of the fraction bar, the two contributions add in magnitude instead of partially cancelling.

  5. Divide and interpret the sign.

    x=9647.3925=385.8956x=\frac{9647.39}{-25}=-385.8956

    It is exact, not rounded, since 9647.39/259647.39/25 terminates. The value differs from 1279.43-1279.43, so the denominator is not zero and the solution is admissible.

  6. Check by substituting back. Numerator: 1202.61(385.8956)=1588.50561202.61-(-385.8956)=1588.5056. Denominator: 1279.43+(385.8956)=893.53441279.43+(-385.8956)=893.5344. Their ratio is 1588.5056/893.5344=1.77=16/91588.5056/893.5344=1.7\overline{7}=16/9 ✓.

Answer

x=385.8956x=-385.8956

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