Solve for :
Tidy the numerator before doing anything structural. The two constants combine:
so the equation is . Note that appears in both numerator and denominator with opposite signs, which is what makes the final coefficient large.
Cross-multiply. For with , the equation is equivalent:
Keep in mind the hidden restriction , i.e. ; we will check the answer against it at the end.
Expand both sides.
Collect the terms and the constants. Subtracting and from both sides:
The coefficient comes from : because sat on opposite sides of the fraction bar, the two contributions add in magnitude instead of partially cancelling.
Divide and interpret the sign.
It is exact, not rounded, since terminates. The value differs from , so the denominator is not zero and the solution is admissible.
Check by substituting back. Numerator: . Denominator: . Their ratio is ✓.
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