Solve
giving correct to two decimal places.
Split the left-hand fraction. Dividing each term of the numerator separately turns it into a constant plus a multiple of ; note the produces a negative coefficient:
Expand the product.
so the second term is .
Split the right-hand fraction.
Collect the x terms on the left and the constants on the right.
Divide and round.
Check by substitution. With : the left side is , and the right side is — agreeing to five decimal places, the residual coming only from the six-decimal rounding of the intermediates.
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