Algebra · real student question

Solve (7.26 − x)/4.51 + 2.18 × (8.79x + 7.37) = (3.84x + 28.32)/6.45, giving x correct to two decimal places.

Question

Solve

7.26x4.51+2.18(8.79x+7.37)=3.84x+28.326.45\frac{7.26-x}{4.51}+2.18(8.79x+7.37)=\frac{3.84x+28.32}{6.45}

giving xx correct to two decimal places.

Step-by-step solution

  1. Split the left-hand fraction. Dividing each term of the numerator separately turns it into a constant plus a multiple of xx; note the x-x produces a negative coefficient:

    7.26x4.51=7.264.5114.51x=1.6097560.221729x\frac{7.26-x}{4.51}=\frac{7.26}{4.51}-\frac{1}{4.51}x=1.609756-0.221729x

  2. Expand the product.

    2.18×8.79=19.1622,2.18×7.37=16.06662.18\times 8.79=19.1622,\qquad 2.18\times 7.37=16.0666

    so the second term is 19.1622x+16.066619.1622x+16.0666.

  3. Split the right-hand fraction.

    3.84x+28.326.45=0.595349x+4.390698\frac{3.84x+28.32}{6.45}=0.595349x+4.390698

  4. Collect the x terms on the left and the constants on the right.

    0.221729x+19.1622x0.595349x=4.3906981.60975616.0666-0.221729x+19.1622x-0.595349x=4.390698-1.609756-16.0666

    18.345122x=13.28565818.345122x=-13.285658

  5. Divide and round.

    x=13.28565818.345122=0.7242070.72x=\frac{-13.285658}{18.345122}=-0.724207\approx -0.72

    x=0.72\boxed{x=-0.72}

  6. Check by substitution. With x=0.724207x=-0.724207: the left side is 7.9842074.51+2.18(1.004220)=1.770334+2.189201=3.959535\tfrac{7.984207}{4.51}+2.18(1.004220)=1.770334+2.189201=3.959535, and the right side is 2.780955+28.326.45=25.5390456.45=3.959542\tfrac{-2.780955+28.32}{6.45}=\tfrac{25.539045}{6.45}=3.959542 — agreeing to five decimal places, the residual coming only from the six-decimal rounding of the intermediates.

Answer

x0.72x\approx -0.72

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