Find the root of
Record the excluded value first. The denominator vanishes at , so whatever root appears, it must not equal . Noting this before clearing the fraction is what makes the final check meaningful.
Multiply both sides by (x + 6).
This is legitimate exactly because makes the multiplier non-zero.
Expand and collect.
Check the root against the exclusion. , so the root is admissible.
Verify in the original equation. , and . The sign works out because a positive numerator over a negative denominator is negative, as the right-hand side demands.
Need to solve a different problem like this? Open the solver →