Algebra · real student question

Solve 0.85x x 1.09 x 0.7 = 3250000/2.

Question

Solve 0.85x1.090.7=325000020.85x \cdot 1.09 \cdot 0.7 = \dfrac{3250000}{2} for xx.

Step-by-step solution

  1. Reduce the right-hand side. 3,250,0002=1,625,000\dfrac{3{,}250{,}000}{2} = 1{,}625{,}000, giving 0.85x1.090.7=1,625,0000.85x \cdot 1.09 \cdot 0.7 = 1{,}625{,}000.

  2. Merge the three factors into one coefficient. 0.851.09=0.9265,0.92650.7=0.64855.0.85 \cdot 1.09 = 0.9265, \qquad 0.9265 \cdot 0.7 = 0.64855. A 15%15\% cut, then a 9%9\% rise, then a 30%30\% cut leaves 64.855%64.855\% of the starting value - note this is not 15+93015+9-30 percent, because percentage changes compound multiplicatively.

  3. Solve the resulting one-step equation. 0.64855x=1,625,000x=1,625,0000.64855.0.64855x = 1{,}625{,}000 \quad\Longrightarrow\quad x = \frac{1{,}625{,}000}{0.64855}.

  4. Evaluate exactly, then round. Clearing the decimal, x=32,500,000,00012,9712,505,589.39x = \dfrac{32{,}500{,}000{,}000}{12{,}971} \approx 2{,}505{,}589.39.

  5. Verify the chain forward. 2,505,589.3917×0.85=2,129,751.9832{,}505{,}589.3917 \times 0.85 = 2{,}129{,}751.983, ×1.09=2,321,429.661\times 1.09 = 2{,}321{,}429.661, ×0.7=1,625,000.00\times 0.7 = 1{,}625{,}000.00 - back to the target.

  6. Compare with the 0.85 sibling. Replacing the last factor 0.850.85 by 0.70.7 shrinks the net multiplier from 0.7875250.787525 to 0.648550.64855, so the required xx grows by the ratio 0.7875250.648551.2143\tfrac{0.787525}{0.64855} \approx 1.2143: from about 2.062.06 million to about 2.512.51 million.

Answer

x=16250000.64855=32500000000129712,505,589.39x = \frac{1625000}{0.64855} = \frac{32500000000}{12971} \approx 2{,}505{,}589.39

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