Algebra · real student question

Simplify the exponential expression: the quantity negative 35 a squared b cubed over 7 a to the eighth b to the negative fifth, all cubed.

Question

Simplify the exponential expression:

(35a2b37a8b5)3\left(\frac{-35a^2b^3}{7a^8b^{-5}}\right)^3

Step-by-step solution

  1. Simplify inside the parentheses first. Cubing a messy quotient triples every mistake, so reduce the base before applying the outer power.

  2. Divide the coefficients. 35÷7=5-35 \div 7 = -5.

  3. Apply the quotient rule to each variable. For aa: a28=a6a^{2-8} = a^{-6}. For bb: b3(5)=b8b^{3-(-5)} = b^{8}. Subtracting a negative exponent adds, which is where sign errors usually creep in.

  4. Rewrite the base. The parentheses now hold 5a6b8=5b8a6-5a^{-6}b^{8} = \dfrac{-5b^8}{a^6}.

  5. Raise everything to the third power. (5)3=125(-5)^3 = -125, (b8)3=b24(b^8)^3 = b^{24} and (a6)3=a18(a^6)^3 = a^{18}; the odd power keeps the result negative.

  6. State the answer with positive exponents. 125b24a18\dfrac{-125b^{24}}{a^{18}}.

Answer

125b24a18-\frac{125b^{24}}{a^{18}}

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