Solve for :
Identify the coefficients and pick the right tool. Here Nothing factors over the integers and completing the square would force a division by at the very first move, so the quadratic formula is the cleanest route.
Compute the discriminant with full precision. Rounding to, say, this early would already move the roots in the third decimal place, because the next step divides by the small number and magnifies every error tenfold.
Take the square root. Since the equation has two distinct real roots, which is what we should expect from a parabola opening upward with a negative linear coefficient and a positive constant.
Divide by . With , Taking the plus sign, and taking the minus sign,
Check both roots by substitution and by the coefficient identities. Substituting and back into gives to ten decimal places. As a second check, the sum of the roots should be and indeed ; the product should be and .
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