Algebra · real student question

Printer A can print a certain number of pages in 7 hours and printer B can print the same number in 3 hours. Both printed for 5 hours, and printer A produced 1800 pages in that time. How many pages can printer B print in 5 hours?

Question

Printer A can print a certain number of pages in 77 h. Printer B can print the same number of pages in 33 h. Both printers started printing at the same time for 55 h.

How many pages can Printer B print in 55 h, given that Printer A printed 18001800 pages in the 55 h?

Step-by-step solution

  1. Convert times into rates. Let NN be the size of the shared job in pages. Then

    rA=N7 pages/h,rB=N3 pages/h.r_A=\frac{N}{7}\ \text{pages/h},\qquad r_B=\frac{N}{3}\ \text{pages/h}.

    Rates, not times, are what add and scale linearly — this is the move that makes every work problem routine.

  2. Use A's actual output to find its rate. Printer A produced 18001800 pages in 55 h, so

    rA=18005=360 pages/h.r_A=\frac{1800}{5}=360\ \text{pages/h}.

  3. Recover the job size N. Since rA=N7r_A=\tfrac{N}{7},

    N=7rA=7(360)=2520 pages.N=7r_A=7(360)=2520\ \text{pages}.

  4. Find B's rate.

    rB=N3=25203=840 pages/h.r_B=\frac{N}{3}=\frac{2520}{3}=840\ \text{pages/h}.

    Notice rB/rA=73r_B/r_A=\tfrac{7}{3}: B is faster in exactly the inverse ratio of the times, which is the shortcut route to the same place.

  5. Multiply by the 5 hours.

    1800×73=840×5=4200 pages.1800\times\frac{7}{3}=840\times 5=4200\ \text{pages}.

  6. Sanity-check the result. In 55 h, B does 53\tfrac53 of the whole job (55 h out of the 33 h it needs), and 53×2520=4200\tfrac53\times 2520=4200 ✓. Likewise A does 57\tfrac57 of the job: 57×2520=1800\tfrac57\times 2520=1800 ✓, matching the given figure.

Answer

4200 pages4200\ \text{pages}

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