Algebra · real student question

Given 36 + 2mx = 88 and x = 2, find the value of m.

Question

Given that

36+2mx=8836+2mx=88

and x=2x=2, find mm.

Step-by-step solution

  1. Decide which letter is the unknown. The equation contains two letters, but xx is given as 22, so the only thing left to determine is mm. Substituting the known value first is what turns a two-variable equation into an ordinary one-variable one.

  2. Substitute x=2x=2.

    36+2m(2)=8836+2m(2)=88

    Both the 22 from the coefficient and the 22 from xx multiply the mm — they do not add.

  3. Simplify the mm term.

    2m2=4m36+4m=882m\cdot 2=4m\quad\Rightarrow\quad 36+4m=88

  4. Undo the addition. Subtract 3636 from both sides:

    4m=8836=524m=88-36=52

  5. Divide by the coefficient and check.

    m=524=13m=\frac{52}{4}=13

    Substituting back: 36+2(13)(2)=36+52=8836+2(13)(2)=36+52=88 ✓. So m=13m=13.

Answer

m=13m=13

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