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Algebra · real student question

Simplify the expression 5(x − 3)(x² + 4x + 1).

Question

Simplify

5(x−3)(x2+4x+1)5(x-3)(x^{2}+4x+1)

Step-by-step solution

  1. Choose an order that keeps the numbers small. Multiplication is associative, so you may take (x−3)(x2+4x+1)(x-3)(x^2+4x+1) first and save the factor of 55 for last. Multiplying the 55 in at the start would force you to carry 5x5x and −15-15 through every partial product.

  2. Distribute x over the trinomial.

    x(x2+4x+1)=x3+4x2+xx(x^{2}+4x+1)=x^{3}+4x^{2}+x

  3. Distribute −3 over the trinomial. Watch every sign:

    −3(x2+4x+1)=−3x2−12x−3-3(x^{2}+4x+1)=-3x^{2}-12x-3

  4. Add the two partial products.

    x3+(4x2−3x2)+(x−12x)−3=x3+x2−11x−3x^{3}+(4x^{2}-3x^{2})+(x-12x)-3=x^{3}+x^{2}-11x-3

  5. Multiply through by 5. This is the step most often skipped:

    5(x3+x2−11x−3)=5x3+5x2−55x−155\left(x^{3}+x^{2}-11x-3\right)=5x^{3}+5x^{2}-55x-15

    5x3+5x2−55x−15\boxed{5x^{3}+5x^{2}-55x-15}

  6. Check by substitution, and beware the answer options. At x=1x=1 the original is 5(−2)(6)=−605(-2)(6)=-60, and the expansion gives 5+5−55−15=−605+5-55-15=-60. ✓ Note that the commonly printed choice 5x3+x2−11x−35x^3+x^2-11x-3 is the product before the 55 is distributed, and the other listed choices do not match either — so on a multiple-choice version of this item the honest answer is that none of the options is correct.

Answer

5x3+5x2−55x−155x^{3}+5x^{2}-55x-15

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