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Algebra · real student question

Evaluate -28.9 ln(x) + 64.449 when x = 90.1.

Question

Evaluate

−28.9ln⁡(x)+64.449-28.9\ln(x)+64.449

when x=90.1x=90.1.

Step-by-step solution

  1. Substitute and note the order of operations. The expression becomes

    −28.9ln⁡(90.1)+64.449-28.9\ln(90.1)+64.449

    The logarithm is evaluated first, then multiplied by −28.9-28.9, and only then is 64.44964.449 added. In particular this is not ln⁡\ln of anything times xx, and the +64.449+64.449 is outside the logarithm.

  2. Compute the natural logarithm to enough digits. To six decimal places,

    ln⁡(90.1)=4.500920\ln(90.1)=4.500920

    A useful cross-check: ln⁡90.1=ln⁡9.01+ln⁡10≈2.198335+2.302585=4.500920\ln 90.1=\ln 9.01+\ln 10\approx 2.198335+2.302585=4.500920. ✓ Because the multiplier −28.9-28.9 is large, every digit you drop here is magnified about 29 times, so do not round to four decimals yet.

  3. Multiply by the coefficient.

    −28.9×4.500920=−130.076588-28.9\times 4.500920=-130.076588

    The sign is negative because −28.9<0-28.9<0 and ln⁡(90.1)>0\ln(90.1)>0.

  4. Add the constant term.

    −130.076588+64.449=−65.627588≈−65.63-130.076588+64.449=-65.627588\approx -65.63

  5. See what a coarse logarithm value would have cost. Using ln⁡(90.1)≈4.5017\ln(90.1)\approx 4.5017 instead gives −28.9×4.5017=−130.099-28.9\times 4.5017=-130.099 and a final value of −65.65-65.65. That is off by about 0.0230.023 — enough to move the answer to −65.65-65.65 instead of −65.63-65.63, and the reason to look the logarithm up to six digits instead of trusting a remembered value.

Answer

−65.63-65.63

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