Algebra · real student question

Evaluate the expression C = 8x^3 + 12x^3 + 6x + 1 at x = 1/2.

Question

Find the value of

C=8x3+12x3+6x+1at x=12C=8x^3+12x^3+6x+1\qquad\text{at }x=\frac12

Step-by-step solution

  1. Combine like terms first. 8x38x^3 and 12x312x^3 have the same variable part, so they add directly:

    8x3+12x3=20x38x^3+12x^3=20x^3

    Doing this before substituting means computing (12)3\left(\tfrac12\right)^3 once instead of twice.

  2. Write the reduced expression.

    C=20x3+6x+1C=20x^3+6x+1

  3. Compute the cube of the fraction.

    (12)3=182018=208=52\left(\frac12\right)^3=\frac{1}{8}\quad\Longrightarrow\quad 20\cdot\frac18=\frac{20}{8}=\frac52

    Remember the exponent applies to numerator and denominator alike: 1323=18\tfrac{1^3}{2^3}=\tfrac18.

  4. Compute the linear term.

    612=36\cdot\frac12=3

  5. Add the three pieces over a common denominator.

    C=52+3+1=52+4=52+82=132C=\frac52+3+1=\frac52+4=\frac52+\frac82=\frac{13}{2}

  6. Check as a decimal. 20(0.125)+6(0.5)+1=2.5+3+1=6.5=13220(0.125)+6(0.5)+1=2.5+3+1=6.5=\tfrac{13}{2}. \checkmark

Answer

C=132=6.5C=\frac{13}{2}=6.5

Need to solve a different problem like this? Open the solver →