Algebra · real student question

An arithmetic sequence has first term u1 = 3 and common difference d = 2. Find u5.

Question

An arithmetic sequence (un)(u_n) has first term u1=3u_1=3 and common difference d=2d=2. Find u5u_5.

A. 1111 B. 1515 C. 1212 D. 1414

Step-by-step solution

  1. Recall the nth-term rule. Every arithmetic sequence satisfies un=u1+(n1)du_n=u_1+(n-1)d The factor is n1n-1, not nn, because you take dd steps only between terms.

  2. Identify the three inputs. Here u1=3u_1=3, d=2d=2 and the target index is n=5n=5, so there are 51=45-1=4 steps of size 22 from the first term.

  3. Substitute. u5=3+(51)2=3+8=11u_5=3+(5-1)\cdot 2=3+8=11

  4. Verify by listing the terms. u1=3u_1=3, u2=5u_2=5, u3=7u_3=7, u4=9u_4=9, u5=11u_5=11 — the listed value matches the formula.

  5. Watch the off-by-one trap. Using u1+nd=3+5(2)=13u_1+nd=3+5(2)=13 or the option 1515 (which is u7u_7) both come from miscounting the steps. The correct answer is A, u5=11u_5=11.

Answer

u5=3+(51)2=11u_5=3+(5-1)\cdot 2=11

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